3x^2-72x+240=0

Solution for 3x^2-72x+240=0 equation:

3x^2-72x+240=0

a = 3; b = -72; c = +240;
Δ = b2-4ac
Δ = -722-4·3·240
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-48}{2*3}=\frac{24}{6}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+48}{2*3}=\frac{120}{6}
=20
$